Using or with strfind

v k
2021 2 12
1 个回答
更新时间：2021 2 12
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Hello,
I have two patterns p1 (or) p2, to be found within a single string, str. The objective is to get the position if either of those two patterns is found. But the following doesn't seem to work:
position=strfind(str,p1 || p2)
How to modify this statement to get the result?
Thanks.

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回答（1 个）

KSSV
KSSV 2021-2-12

0 个投票

position1 = strfind(str,p1) ;
position2 = strfind(str,p2) ;
OR
position = strfind(str,[p1, p2]) ;

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v k
v k 2021-2-12
Thanks. But doesn't seem to work.
str='<s 123>item1<m>list unwanted<dfy 97>item2<m>';
p1='<s 123>';
p2='<dfy 97>';
p3='<m>';
startPosition=strfind(str,[p1,p2]);
startPosition=startPosition+numel(p1);
endPosition=strfind(str,p3);
endPosition=endPosition-1;
This gives
startPosition =
[]
Also, how to resolve the fact the lengths of p1 and p2 are different, and hence, there is a mismatch in the startPosition when adding numel(p*) to it?
v k
v k 2021-2-12
The objective is to extract out the items: item1 and item2.
KSSV
KSSV 2021-2-12
position1 = strfind(str,p1) ;
position2 = strfind(str,p2) ;

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v k
v k
2021-2-12

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KSSV
KSSV
2021-2-12

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