How to calculate sum without loop?

2021 2 12
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更新时间：2021 2 12
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Hello,
I must calculate S in the range of n=1 to n=100 without a loop.
s=(1...100)(101-n)*cos(n/100)
Example= 100*cos(1/100) + 99*cos(2/100) ... + 1*cos(100/100)

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回答（1 个）

KSSV
KSSV 2021-2-12

2 个投票

n = 1:100 ;
s = sum(n.*cos(n/100))

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Aditya Kommajosula
Aditya Kommajosula 2021-2-12
编辑：Aditya Kommajosula 2021-2-12
If I understand the OP's question right, the solution might have to be:
n = 1:100;
s = sum(n(end:-1:1).*cos(n/100));
Regards
Numerical Noob
Numerical Noob 2021-2-12
Thank you Aditya, I tried it with an iterative approach with n=1..3. Your solution is right.

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