Addition of numbers in array

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Muhammad Usman
Muhammad Usman 2021-2-13
评论： Steven Lord 2021-2-16
Lets' say I have 2 vectors:
x = [7 4 6];
y = [1 4 4];
But these are not just vector consider them as A number, i.e., 746 and 144. Now I want to add these numbers (as we do on paper, carry method).
so the answer should be 890.
and want display like:
7 4 6
1 4 4
-----
8 9 0
Please help me to code.
Thanks

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Ameer Hamza
Ameer Hamza 2021-2-13
This is one way
x = [7 4 6];
y = [1 4 4];
z = sscanf(sprintf('%d',x),'%d')+sscanf(sprintf('%d',y),'%d')
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Muhammad Usman
Muhammad Usman 2021-2-15
@KALYAN ACHARJYA, I am following your lines of code, but generating error when I do:
x = randi([0,9],1,20);
y = randi([0,9],1,20);
x_new = str2double(sprintf('%d',x));
y_new = str2double(sprintf('%d',y));
result = num2str(x_new+y_new) - '0';
fprintf('%4d',x);
fprintf('\n');
fprintf('%4d',y);
fprintf('\n');
disp('+');
disp('-------------------------------------------------------------------------')
fprintf('%d',result);
fprintf('\n')
The ouput I get (which is wrong):
9 6 1 3 0 5 4 9 8 4 8 1 3 9 9 7 6 3 9 1
7 6 8 3 7 8 3 5 9 5 3 6 3 7 4 4 6 9 3 8
+
-------------------------------------------------------------------------
1-272968385801777453-520
can you please mention the mistake in running these lines. And help me to align (with same gap spaces) the result
Steven Lord
Steven Lord 2021-2-16
Ran in:
Your numbers are too large to guarantee that they can be stored exactly as double precision numbers.
x = 96130549848139976391;
rem(x, 10) % ones digit
ans = 8
spacing = eps(x)
spacing = 16384
The spacing between consecutive representable numbers in the vicinity of x is 16,384. It is too large even to be stored exactly as a uint64 number.
y = uint64(96130549848139976391) % Saturated at intmax
y = uint64 18446744073709551615
You will need to store your numbers and perform calculations in arbitrary precision arithmetic, like in Symbolic Math Toolbox.
s = sym('96130549848139976391')
s = 
96130549848139976391

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