Plotting Functions using For Loop and If Statements?
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Hey all,
I'm attempting to write a program using a for loop and conditional statements for the following:
I thought this was a very simple assignment but however when I try to implement my code my plot comes up completely blank. This is my first time working with MATLAB so apologies if this is trivial to most of you. Could someone help me understand what I'm doing wrong? Thanks in advance.
Below is my code:
t=0;
x1= ((t.^2)-(2*t)+3);
x2 = (4*cos((2*pi*t)-(pi/8))+3*sin(2*pi*t));
x3 = (sinc(t));
figure(1);
hold on
for i= -4:0.1:4
if (i> - 4) && (i< -2)
t = i;
y = x1;
elseif (i >-2) && (i < 2)
t = i;
y = x2;
elseif (i > 2) && (i< 4)
t = i;
y = x3;
end
plot(t,y)
end
采纳的回答
KALYAN ACHARJYA
2021-2-17
编辑：KALYAN ACHARJYA
2021-2-17
t=-4:0.1:4
x1= (t.^2)-(2*t)+3;
x2 = 4*cos((2*pi*t)-(pi/8))+3*sin(2*pi*t);
x3 = sinc(t);
y=zeros(1,length(t));
for i=1:length(t)
if (t(i)>-4) && (t(i)< -2)
y(i)= x1(i);
elseif (t(i)>-2) && (t(i) < 2)
y(i)= x2(i);
else
y(i)= x3(i);
end
end
figure,plot(t,y);
Important: Here you can avoid loop and if else condition (recommended), please try once, we are here to help you.
4 个评论
KALYAN ACHARJYA
2021-2-17
编辑：KALYAN ACHARJYA
2021-2-17
Here: Without Loop and if else Statement
t=-4:0.1:4;
x1= (t.^2)-(2*t)+3;
x2 = 4*cos((2*pi*t)-(pi/8))+3*sin(2*pi*t);
x3 = (sinc(t));
y=x3;
id1=t>-4 & t<-2;
id2=t>-2 & t<2;
y(id1)=x1(id1);
y(id2)=x2(id2);
figure,plot(t,y);
Nicholas Ross
2021-2-17
KALYAN ACHARJYA
2021-2-17
This is logical indexing, Here the links
https://blogs.mathworks.com/loren/2013/02/20/logical-indexing-multiple-conditions/
https://in.mathworks.com/help/matlab/matlab_prog/techniques-for-improving-performance.html
Nicholas Ross
2021-2-17
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