Variable of one implicit function used in another?
显示 更早的评论
Hi,
I have a function that I am not able to isolate by hand
2.31525+0.231525*sin(2*pi*x)-(1+.2*m.^2).^3/m
where x runs from 0 to 1.
I was able to plot this using fimplicit, but now I want to plot another function that uses these same m values as an input. What is the easiest way to do this?
I am new to matlab and only used one line of code:
fimplicit(@(x,m)2.31525+0.231525*sin(2*pi*x)-(1+.2*m.^2).^3/m,[0 1])
thanks!
采纳的回答
David Hill
2021-2-18
function out = eqn(x)
b=@(m)2.31525+0.231525*sin(2*pi*x)-(1+.2*m.^2).^3/m;
out=fsolve(b,.5);
end
x=0:.01:1;
y=zeros(size(x));
for k=1:length(x)
y(k)=eqn(x(k));
end
plot(x,y);
4 个评论
Michael P. Cohen
2021-2-18
Walter Roberson
2021-2-18
If you put both in the same file then the function needs to be after the script.
Michael P. Cohen
2021-2-18
David Hill
2021-2-18
function out = eqn(x)
b=@(m)2.31525+0.231525*sin(2*pi*x)-(1+.2*m.^2).^3/m;
out=fsolve(b,.5);
end
Establish function, then run script:
x=0:.01:1;
y=zeros(size(x));
for k=1:length(x)
y(k)=eqn(x(k));
end
t =@(m) 315./(1+.2*m.^2);
p =@(m) (1.186./((1+.2*m.^2).^-3.5));
subplot(3,1,1);
plot(x,y);
subplot(3,1,2);
plot(x,t(y));
subplot(3,1,3);
plot(x,p(y));
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Logical 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
