Computation on arrays using loops

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Hello,
I want to create code that will do operations on specified values from the arrays. I have array X and array Y, where array Y is X-dependent. Array X looks more or less like this: [0 0 0 0 0 0 0 0 0 0 0 45.9 45.98 45.99 46 46 46 46 0 0 0 0 0 0 0 ...], it represents pulse-like behaviour. I want matlab to save in workspace the values of array Y that corresponds to the every last "0" of the array X before the pulse ''46'' happens on the length of the whole array.
I expect that for/while loop has to be applied, but I am not sure which one and how the statements should look like. I would appreciate any help. Thank You. I am using matlab2020b version.

采纳的回答

Stephen23
Stephen23 2021-2-19
Y = [2.659717,2.656496,2.656496,2.656173,2.662294,2.661328,2.660039,2.620416,2.614295,2.606242,2.600765,2.600443,2.590779,2.591745,2.590457,2.586913,2.58498,2.583048,2.585303,2.578216,2.577571,2.580793,2.57886,2.573061,2.575638]
Y = 1×25
2.6597 2.6565 2.6565 2.6562 2.6623 2.6613 2.6600 2.6204 2.6143 2.6062 2.6008 2.6004 2.5908 2.5917 2.5905 2.5869 2.5850 2.5830 2.5853 2.5782 2.5776 2.5808 2.5789 2.5731 2.5756
X = [0,0,0,0,0,0,0,46.24,46.24,46.24,46.24,46.24,46,46,46,46,46,45.99,45.99,45.99,45.99,45.99,46,46,46,46,46,46,46,46,46,46,46]
X = 1×33
0 0 0 0 0 0 0 46.2400 46.2400 46.2400 46.2400 46.2400 46.0000 46.0000 46.0000 46.0000 46.0000 45.9900 45.9900 45.9900 45.9900 45.9900 46.0000 46.0000 46.0000 46.0000 46.0000 46.0000 46.0000 46.0000
idx = diff(X~=0)>0;
out = Y(idx)
out = 2.6600
  6 个评论
Kacper Witasinski
Kacper Witasinski 2021-2-23
编辑:Kacper Witasinski 2021-2-23
Works, but one note for people dealing with same problem in the future. Matlab returned an error "Dimensions of matrices being concatenated are not consistent." After I transposed idx everything works perfectly.
Regards and thank You once more Stephen.

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更多回答(2 个)

Steven Lord
Steven Lord 2021-2-22
Since you seem to be describing change point detection, see the ischange function and/or the Find Change Points task in the Live Editor.

KALYAN ACHARJYA
KALYAN ACHARJYA 2021-2-19
编辑:KALYAN ACHARJYA 2021-2-19
"I want matlab to save in workspace the values of array Y that corresponds to the every last "0" of the array X before the pulse ''46'' happens on the length of the whole array."
Is this? Note for this problem loop can be avoided
idx=find(diff(X)==-46)+1
This idx gives the indices of x, where x equal to zero and it's corresponding previous data to be equal to 46
Afterwards
Y=X(idx)
  3 个评论
KALYAN ACHARJYA
KALYAN ACHARJYA 2021-2-19
编辑:KALYAN ACHARJYA 2021-2-19
Yes as per my code gives transition indices (from 46 to 0 only)
Can you clarify again? In this X example, what would be the Y
X=[0 0 0 0 0 0 0 0 0 0 0 45.9 45.98 45.99 46 46 46 46 0 0 0 0 0 0 0 ]
Kacper Witasinski
Kacper Witasinski 2021-2-19
编辑:Kacper Witasinski 2021-2-19
The values of X array given by me are really exemplary values that should give general scope of the behaviour.
Corresponding values of Y are more or less constant (the difference is in third/fourth number after the decimal point) for zeros of X array. When the pulse happen, the values are decreasing in exponential way and then values are increasing in exponential way when pulse ends. I can show You how graphs looks like to give You the idea.
So I will write once again. For majority of time the values of array X are equal to 0. At some instant, there is a pulse and the values of array Y decrease. I need the exact values of array Y that corresponds to the last zero value of array X before the pulse happen for the whole length of array (Imagine that there are 10 pulses).
Small fragment of my data:
Y= [2,659717 2,656496 2,656496 2,656173 2,662294 2,661328 2,660039 2,620416 2,614295 2,606242 2,600765 2,600443 2,590779 2,591745 2,590457 2,586913 2,58498 2,583048 2,585303 2,578216 2,577571 2,580793 2,57886 2,573061 2,575638]
X=[0 0 0 0 0 0 0 46,24 46,24 46,24 46,24 46,24 46 46 46 46 46 45,99 45,99 45,99 45,99 45,99 46 46 46 46 46 46 46 46 46 46 46 and so on]
Please, dont mind comas.

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