清空筛选条件
清空筛选条件

How do I generate the first four polynomials?

2 次查看（过去 30 天）
veru
veru 2013-5-10
A Legendre polynomial of degree n is given by the following expression: Pn(x)=1/(2^n*n!) * nth derivative of (x^2-1)^n
How do I generate the first four polynomials?
I have tried the following code but no output is being given:
function y=f(x,n)
function z=S(w,n)
for k=4
syms w
z=(w^2-1)^n
subs(S,w,x)
diff(S,n);
y=(1/2^n)*factorial(n)*S
subs(f,w,x)
end
Thanks in advance.

请先登录，再回答此问题。

采纳的回答

Friedrich
Friedrich 2013-5-10
编辑：Friedrich 2013-5-10
Hi,
what about:
for i=1:4
P{i} = 1/(( 2^i)*factorial(i)) * diff(sym(['(x^2-1)^',num2str(i)]),i)
end
Since you have Symbolic MATH Toolbox you can also do:
for i=1:4
L{i} = feval(symengine,'orthpoly::legendre',i,'x');
end

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Polynomials 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by