represent exponential function in app designer

Question

Alvaro Mª Zumalacarregui Delgado 2021-2-22

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/753219-represent-exponential-function-in-app-designer

回答： Abhishek Chakram 2023-10-11

How can I put the initial condition to the functions y1 and y2? Because the interface doesn't draw in the axes the function that I want and maybe it is due to the fact that my code doesn't have the initial condition, this is my code:

P = app.P.Value;

Q = app.Q.Value;

Xo = app.Xo.Value;

Yo =app.Yo.Value;

a = app.a.Value;

b = app.b.Value;

Ky = Yo-P/a;

Kx = Xo-Q/a;

C2 = (Ky.*sqrt(a/b)+Kx)/(2.*sqrt(a/b));

C1 = Ky-C2;

x = 0:0.2:100;

y1 = (- C1*sqrt(a/b)*exp(sqrt(a*b)*x) + C2*sqrt(a/b)*exp(-sqrt(a*b)*x)) + Q/b;

plot (app.Axes,x,y1,'k')

y2 = (C1*exp(sqrt(a*b)*x) + C2*exp(-sqrt(a*b)*x)) + P/a;

hold (app.Axes, 'on');

plot (app.Axes,x,y2,'g')

hold (app.Axes,'off')

thanks!

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Answer 1

Abhishek Chakram 2023-10-11

0
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https://ww2.mathworks.cn/matlabcentral/answers/753219-represent-exponential-function-in-app-designer#answer_1330549

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Hi Alvaro Mª Zumalacarregui Delgado,

It is my understanding that you want to add initial conditions to the functions y1 and y2. Here is an example for the same:

x = 1:10;
y1_initial = 0; % Intial y1 value
y2_initial = 4; % Intial y2 value
y1 = [y1_initial,cos(x)]; % Assigning intial y1 value
y2 = [y2_initial,sin(x)]; % Assigning intial y2 value
plot(y1,y2,'*');