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How to plot the phase portrait of a second-order differential equation? I cannot use quiver

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Batuhan Bilen
Batuhan Bilen 2021-2-23
评论： Batuhan Bilen 2021-2-27
𝑥̈+ 𝑥̇ − 𝑥 − 𝑥 2 = 0
b. 𝑥̈+ 4𝑥̇ + 4𝑥 = 0
c. 𝑥̈− 2𝑥̇ + 2𝑥 = −8
d. 𝑥̈− 2𝑥 − 𝑥̇ − 2 = 0
I need to plot the phase portrait of these systems. What is wrong?
syms t
syms x(t)
dx=diff(x);
d2x=diff(x,2);
eq=d2x+dx-x-x.^2==0;
t=linspace(-1,1,100);
for n=1:5
s1=dsolve(eq,x(0)==n,dx(0)==n);
s2=diff(s1);
s1=subs(s1);
s2=subs(s2);
plot(s1,s2);
hold on
n=n+1;
end

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采纳的回答

SaiDileep Kola
SaiDileep Kola 2021-2-26
Check the answer on similar question answered here

更多回答（1 个）

Shadaab Siddiqie
Shadaab Siddiqie 2021-2-26
From my understanding you want to plot symbolic equation. Please refer ezplot which might help you.

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