Matlab and batch file

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Aleksander 2013-5-11

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回答： Maria Sheeba 2017-3-9

Hi.

-i am not the most experienced matlab programer how ever, i am trying to exploite an batch script that i have previously writen.

by using uigetfile i will get an array of file names in Filnames i.e test.txt test2.txt test3.txt

i wish to pass this along to the batch script. and have tried !C:\test.bat Filnames(:,1) Filnames(:,2) Filnames(:,3)

but the batch script only recive the text as above: Echo Filnames(:,1) ......

any solultion to pass the found filname to an batch script ?

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Answer 1

per isakson 2013-5-11

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在 MATLAB Online 中打开

I would do it this way

    cmd = sprintf( 'c:\\test.bat %s %s %s', file(:,1), file(:,2), file(:,3) );
    msg = dos( cmd );

because that allows me to inspect cmd. I can even copy&paste cmd to the Command Prompt and check that it works.

Replace dos by system if you are on Unix.

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Aleksander 2013-5-12

This is an possible solution. however since my code is per now like this:

[Filename,Filepath] = uigetfile({'*.txt','LOG FILES,(*.txt)'},'SELECT LOG FILE(S)','C:\','Multiselect','on')

-when you select multiple files thee filenames are resturned in an cell array, which sprintf does not accept.

i am considering to drop the file names in an text file using dlmwirte and then have the batch file read the text file.

per isakson 2013-5-12

I just copied from the code you showed.

Either you handle the list of files in the bat-file or in Matlab, whichever is more convenient.

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Answer 2

Image Analyst 2013-5-11

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Have you seen the FAQ: http://matlab.wikia.com/wiki/FAQ#How_can_I_process_a_sequence_of_files.3F

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Image Analyst 2013-5-12

编辑：Image Analyst 2013-5-12

在 MATLAB Online 中打开

Try this code, which I adapted from the FAQ by inserting your code before it:

startingFolder = fullfile(matlabroot, '\toolbox\images\imdemos');
[baseFileNames, chosenFolder] = uigetfile({'*.*','All Files,(*.*)'},'SELECT LOG FILE(S)',...
  startingFolder,'Multiselect','on')
for k = 1:length(baseFileNames)
  baseFileName = baseFileNames{k};
  fullFileName = fullfile(chosenFolder, baseFileName);
  message = sprintf('Now processing %s', fullFileName);
  fprintf('\n%s\n', message);
  promptMessage = sprintf('%s\n\nDo you want to Continue processing,\nor Cancel to abort processing?', message);
  titleBarCaption = 'Continue?';
  button = questdlg(promptMessage, titleBarCaption, 'Continue', 'Cancel', 'Continue');
  if strcmpi(button, 'Cancel')
    return;
  end
  
end

Aleksander 2013-5-22

在 MATLAB Online 中打开

hi. thanks for the help :) this is the solution i came up with.

    % code
[Filenames,Filepath] = uigetfile({'*.*','LOG FILES ,(*.*)'},'SELECT... LOGFILE(S)','C:\','Multiselect','on');
m = max(size(Filenames));
 mm = (m)-1
 %print single filname only:
 if (m==11)
    basefilename = [Filenames] 
   else  
%print several found file names to a text file.
 Filenames = sort(Filenames);
 basefilename = [''] ;
   for k = 1:length(Filenames);
   Filename = Filenames{k};
     if (mm==(k)-1)
         basefilename = [basefilename Filename];
       else
       basefilename = [basefilename Filename '+'];
      end
    end
 end