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Hi,

Which angle is calculating with this matlab code

a=sensor1; b=sensor2; c=22;

numerator=(b^2)+(c^2)-(a^2); %Täljare demoninator=2*b*c; %Nämnare

cos_alpha=numerator/demoninator;

alpha=acosd(cos_alpha); %The angle alpha in degrees

Can anyone help me in understanding this code

Thanks in advance

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Jim 2013-5-12

The distance between sensors is c=22, a and b are the distance of the sensors from the object. Now which angle is being calculated with this code

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Answer 1

Roger Stafford 2013-5-12

在 MATLAB Online 中打开

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Apparently there is a triangle with vertices A, B, and C with sides opposite to these vertices of length a, b, and c, resectively. The angle, alpha, at vertex A must satisfy the cosine law:

 a^2 = b^2 + c^2 - 2*b*c*cos(alpha)
 cos(alpha) = (b^2+c^2-a^2)/(2*b*c)
 alpha = acosd((b^2+c^2-a^2)/(2*b*c)) (in degrees)

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Jim 2013-5-12

Thanks for ur reply

After calculating the angle what the below command will do?

l=sind(alpha)*b;

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