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problem with the code

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Jim
Jim 2013-5-12
关闭： MATLAB Answer Bot 2021-8-20
Hi,
Which angle is calculating with this matlab code
a=sensor1; b=sensor2; c=22;
numerator=(b^2)+(c^2)-(a^2); %Täljare demoninator=2*b*c; %Nämnare
cos_alpha=numerator/demoninator;
alpha=acosd(cos_alpha); %The angle alpha in degrees
Can anyone help me in understanding this code
Thanks in advance
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Jim
Jim 2013-5-12
The distance between sensors is c=22, a and b are the distance of the sensors from the object. Now which angle is being calculated with this code

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回答（1 个）

Roger Stafford
Roger Stafford 2013-5-12
Apparently there is a triangle with vertices A, B, and C with sides opposite to these vertices of length a, b, and c, resectively. The angle, alpha, at vertex A must satisfy the cosine law:
a^2 = b^2 + c^2 - 2*b*c*cos(alpha)
cos(alpha) = (b^2+c^2-a^2)/(2*b*c)
alpha = acosd((b^2+c^2-a^2)/(2*b*c)) (in degrees)
  1 个评论
Jim
Jim 2013-5-12
Thanks for ur reply
After calculating the angle what the below command will do?
l=sind(alpha)*b;

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