Hi Even,
The electric field strength can be approximated by the gradient of the voltage with respect to distance. Here is a sample code to plot the data:
% Calculate the electric field strength (V/km)
% Assuming the voltageMatrix rows represent different distances
% and columns represent different measurements at those distances
electricFieldStrength = diff(voltageMatrix, 1, 2) ./ diff(distance);
% Adjust the distance array to match the size of electricFieldStrength
distanceMidPoints = (distance(1:end-1) + distance(2:end)) / 2;
% Plotting
figure;
plot(distanceMidPoints, electricFieldStrength);
xlabel('Distance (km)');
ylabel('Electric Field Strength (V/km)');
title('Electric Field Strength vs. Distance');
grid on;
- The diff function computes the difference between adjacent elements. Here, it is used to approximate the gradient of the voltage with respect to distance.
- The result is divided by the distance difference to get the electric field strength in V/km.
- distanceMidPoints is calculated to align the x-axis values with the midpoints of the original distance intervals.
Please share more information regarding the data so that I can provide a more detailed answer.
Hope this helps!
