Find first index that exceeds condition

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Jonathan Cheong
Jonathan Cheong 2021-2-25
评论： Jonathan Cheong 2021-2-25
To elaborate and ensuring my questions are specific, I have a dataset and their index:
[1,2,3,4,5,6,7,8,9]
[1,4,8,0,0,1,9,0,3]
Say I would like to find the index and value of the 1st value > 2 after value (8)
Which means my desired output would look like this:
[7]
[9]
Normally, I would have a table of starting indices, but this is just a random sample to keep it short.
How do I code this?
Thanks.

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回答（1 个）

KALYAN ACHARJYA
KALYAN ACHARJYA 2021-2-25
"I would like to find the index and value of the 1st value > 2 after value (8)"
Is this?
data=[1,4,8,0,0,1,9,0,3]
idx8=find(data==8)
idx=find(diff(data)<0)
result_idx=idx(idx>idx8(1))
Answer would be 7 only, can you verify again?
  2 个评论
Jonathan Cheong
Jonathan Cheong 2021-2-25
Hey Kalyan, thanks for the answer.
Although it technically produces the correct output, it's more like hard coded.
Is there a method to code so that it applies across an entire array consistently?
For example I have attached files: starting index (fdd2), data (rain2).
Same situation just in the format of an array.
Jonathan Cheong
Jonathan Cheong 2021-2-25
The data won't be exactly 0 but it will be less than 2.
Hence the code should stop when the 1st value greater than 2 after the starting index is reached

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