how to choose the value?

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win
win 2013-5-14
i have some data. see below if true
l1 = input('bus connection(choose one number from 1 to 30) = ');
bus1 = [2 3];
bus2 = [1 4 6 5];
bus3 = [1 4];
bus4 = [2 3 6 12];
bus5 = [2 7];
bus6 = [2 4 7 8 9 10 28];
bus7 = [5 6];
bus8 = [6 28];
bus9 = [6 10 11];
bus10 = [6 9 17 20 21 22];
bus11 = 9;
bus12 = [4 13 14 15 16];
bus13 = 12;
bus14 = [12 15];
bus15 = [12 14 18 23];
bus16 = [12 17];
bus17 = [16 10];
bus18 = [15 19];
bus19 = [18 20];
bus20 = [10 19];
bus21 = [10 22];
bus22 = [10 21 24];
bus23 = [15 24];
bus24 = [22 23 25];
bus25 = [24 26 27];
bus26 = 25;
bus27 = [25 28 29 30];
bus28 = [6 8 27];
bus29 = [27 30];
bus30 = [29 27];
end
when i press 1 it display bus1 matrix also when i press 2 it show bus2 matrix and bus3,bus4 etc., please anyone help me
  2 个评论
Thomas
Thomas 2013-5-14
Goodwin, your code will not work as it is. I assume you want the user to input the number and then you want the corresponding bus matrix to show up..
Where do you compare what the user has entered to what you want to look up? you could do this by a number of 'if' statements (just think about it.. ) or use switch case..
win
win 2013-5-14
thanks bro.........

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采纳的回答

Thomas
Thomas 2013-5-14
An example of how to use switch case: adapt for your particular case
busNum=input('Enter the bus number:');
switch busNum
case 1
disp('2 3')
case 2
disp('1 4 6 5')
end

更多回答(2 个)

Jan
Jan 2013-5-14
Storing the values in different variables is a bad idea. Better use an array:
bus = {[2 3], ...
[1 4 6 5], ...
[1 4], ...
etc. };
l1 = input('bus connection(choose one number from 1 to 30) = ');
disp(bus{l1});
  1 个评论
win
win 2013-5-14
thanks bro...... i learned something here. thanks for all of you

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Jurgen
Jurgen 2013-5-14
I suggest you concatenate the numerical input l1 with the string 'bus'. Then display the content with display(). E.g.
X = ['bus' l1];
display(X)
  5 个评论
Jurgen
Jurgen 2013-5-15
Well it should work for this simple case?
José-Luis
José-Luis 2013-5-15
It is not a matter of it working or not. Please look at this previous discussion.

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