Median filter
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I am trying to understand the working of median filter. this is the code %start
A = imread('/*path name*/') ;
A = im2double(A);
[m n] = size(A);
Med = [];
%Modified filter
for i=2:m-1
for j=2:n-1
Med(1) = A(i-1,j-1);
Med(2) =A(i-1,j) ;
Med(3) = A(i-1,j+1);
Med(4) = A(i,j-1);
Med(5) = A(i,j+1);
Med(6) = A(i+1, j-1);
Med(7) = A(i+1,j);
Med(8) = A(i+1,j+1);
A(i,j) = median(Med);
end
end
imshow(A);
but the output is not as expected. it is blurry. need help..
2 个评论
Ahmed
2013-3-28
I tried this code in my research for 2-D medical images and i get a good results better than the standard function of median in matlab and i can send the result to compare between the standard median and this modified one
Changa Hettiarachchi
2020-3-6
Why i get an error in line Med(1)???
采纳的回答
Arturo Moncada-Torres
2011-5-17
To understand the medial filter, maybe it is better if we start in 1D.
Let's suppose the following array:
a = [3 2 1 6 5];
Also, let's suppose you define a window size of n = 3.
You place yourself in the first value of the array, that is 3. Since your window size is 3, you take the sample you are, one sample to the left and one sample to the right. Since this is the first value, there is no sample to the left, so we will just consider a zero:
0 3 2
From this window, you sort the values from minimum to maximum and get the median (the value in the middle)
0 2 3
In this case, the value in the middle is 2. This is the value you write in the filtered vector a_
a_ = [2 2 1 6 5];
Then you go to the next value of a, that is a 2. You take the left sample (which has already been modified) and the right sample
2 2 1
Your sort them and choose the median value (in this case, a 2 again)
1 2 2
So your filtered vector a_ is now
a_ = [2 2 1 6 5];
An so on. In the end, you will have a filtered vector a_
a_ = [2 2 2 5 5];
A median filter in images works the same way, only in 2D. So you take not only the values (pixels) that are left or right, but all the values that surround the sample (pixel) you are in.
In MATLAB, check medfilt1 and medfilt2 ;) .
doc medfilt1;
doc medfilt2;
Anyway, take a look at this useful tutorial http://www.librow.com/articles/article-1 by Chernenko. Even though it is not coded in MATLAB, the explanation is very, very clear.
Keep coding!
4 个评论
Darshan A
2011-5-17
Arturo Moncada-Torres
2011-5-17
I think the problem is that when _median_ receives a matrix as an input, it calculates the median of each column and you need the median of the whole window.
Try something like this:
A(i, j) = median(Med(:));
Let me know if it works ;-) !
Darshan A
2011-5-17
dunklevision
2016-12-18
编辑：dunklevision
2016-12-18
I have an ECG signal which I want to filter with the median filter without using (medfilt1). So I'm supposed to build a function. Can you help me please ?
更多回答（1 个）
Bjorn Gustavsson
2011-5-17
1 个投票
The way you do your itterative medians lead to not taking the median of the input image for pixel [i,j] except for the very first pixel (i=2, j=2). After that (say i=2, j=3) you have overwritten the original pixel value in some of the neighbouring pixels (for the example pixel you'd have the 3-by-3 median in pixel A(2,2), not the original pixel intensity). You should assign the median filtered intensities to pixels in another image array, say Afiltered(i,j).
HTH, Bjeorn
4 个评论
Darshan A
2011-5-17
Bjorn Gustavsson
2011-5-17
What have you tried? Your code "worked", just replace everywhere you assign to A in the median-filtering loop, and the imshow call.
Darshan A
2011-5-18
Andrei Bobrov
2011-5-18
analog function medfil2 <http://www.mathworks.com/matlabcentral/answers/5656-program-to-find-the-median-of-the-matrix-need-to-use-for-loop>
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