count the number of columns 0 and 1 in a barcode image column 0 is black bars and 1 is a white bars

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yen
yen 2011-5-17
I have a barcode image. Please help me how to count the number of columns 0 and 1 in a barcode image only consist column 0 is black bars and 1 is a white bars Please help me.

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回答（3 个）

Ivan van der Kroon
Ivan van der Kroon 2011-5-17
Hey, convert it to logical class and then sum over a column (or columns). If your image is variable Im, go to logical with
BW = im2bw(Im);
Possibly with threshold if your image is not so very black-white in the beginning, see the im2bw help-file. To sum over the columns:
barcode = sum(BW,2);
Where the 2 is for the correct dimension. You can limit BW to a single or multiple row(s) if you want to.
Note that you are counting the number of white pixels in this case. To count the blacks use (1-BW) in the above and if your barcodewidth consists of multiple pixels divide the answer by this number.
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yen
yen 2011-5-18
if I have a imageM
M=
[1 1 0 0 0 0 1 1 1 1 1 0 0 0 1
1 1 0 0 0 0 1 1 1 1 1 0 0 0 1
1 1 0 0 0 0 1 1 1 1 1 0 0 0 1
1 1 0 0 0 0 1 1 1 1 1 0 0 0 1]
how can I count number column 1 and 0?
with M, colmn1=i;
i=8
column0=j;
j=7

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Ivan van der Kroon
Ivan van der Kroon 2011-5-18
>> sum(M,2)
ans =
8
8
8
8
Matt Fig
Matt Fig 2011-5-18
M=[1 1 0 0 0 0 1 1 1 1 1 0 0 0 1
1 1 0 0 0 0 1 1 1 1 1 0 0 0 1
1 1 0 0 0 0 1 1 1 1 1 0 0 0 1
1 1 0 0 0 0 1 1 1 1 1 0 0 0 1]
cnts = histc(double(all(M)),[0 1])
Or, if there will never be a column with some 1s and some 0s, then:
histc(double(M(1,:)),[0 1]) % I don't know if M is logical or what.

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