count the number of columns 0 and 1 in a barcode image column 0 is black bars and 1 is a white bars

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yen 2011-5-17

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I have a barcode image. Please help me how to count the number of columns 0 and 1 in a barcode image only consist column 0 is black bars and 1 is a white bars Please help me.

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Answer 1

Ivan van der Kroon 2011-5-17

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Hey, convert it to logical class and then sum over a column (or columns). If your image is variable Im, go to logical with

BW = im2bw(Im);

Possibly with threshold if your image is not so very black-white in the beginning, see the im2bw help-file. To sum over the columns:

barcode = sum(BW,2);

Where the 2 is for the correct dimension. You can limit BW to a single or multiple row(s) if you want to.

Note that you are counting the number of white pixels in this case. To count the blacks use (1-BW) in the above and if your barcodewidth consists of multiple pixels divide the answer by this number.

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yen 2011-5-18

if I have a imageM

M=

[1 1 0 0 0 0 1 1 1 1 1 0 0 0 1

1 1 0 0 0 0 1 1 1 1 1 0 0 0 1

1 1 0 0 0 0 1 1 1 1 1 0 0 0 1]

how can I count number column 1 and 0?

with M, colmn1=i;

i=8

column0=j;

j=7

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Answer 2

Ivan van der Kroon 2011-5-18

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>> sum(M,2)

ans =

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Answer 3

Matt Fig 2011-5-18

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M=[1 1 0 0 0 0 1 1 1 1 1 0 0 0 1
   1 1 0 0 0 0 1 1 1 1 1 0 0 0 1
   1 1 0 0 0 0 1 1 1 1 1 0 0 0 1
   1 1 0 0 0 0 1 1 1 1 1 0 0 0 1] 
cnts = histc(double(all(M)),[0 1])

Or, if there will never be a column with some 1s and some 0s, then:

histc(double(M(1,:)),[0 1]) % I don't know if M is logical or what.