Simplifying with respect to trig identities to avoid dividing by zero

2 次查看(过去 30 天)
I need to calculate the jacobian for a set of differential equations and the calculation with respect to one variable is particularly complicated.
A working example
syms x y v a psi omega dt
state = [x; y; v; a; psi; omega];
wt = omega * dt / 2;
hwt = psi + wt;
fx = state + [
(v*dt + 0.5*a*dt^2)*cos(hwt)*usinc(wt) + a*dt/omega*sin(hwt)*(cos(wt) - usinc(wt));
(v*dt + 0.5*a*dt^2)*sin(hwt)*usinc(wt) + a*dt/omega*cos(hwt)*(usinc(wt) - cos(wt));
a * dt;
0;
omega * dt;
0
];
dfx_domega = diff(fx(1), omega); % this is the derivative to be simplified
function [ y ] = usinc( x )
%un-normalized sinc function
i=find(x==0);
x(i)= 1; % From LS: don't need this is /0 warning is off
y = sin(x)./(x);
y(i) = 1;
end
The problem is that the derivative results in fractions with ω in the denominator. For this case this is the turn rate which can very possibly be zero, as such I would like to manipulate the equations such that it is not in the denominator as far as possible, this is possible in large by applying .
Is there any way I can apply simplify or rewrite such that the fractions are simplified as such?

回答(1 个)

Hernia Baby
Hernia Baby 2021-2-27
How about using logical indexing?
function [ y ] = usinc( x )
y = sin(x)./(x); % y(x==0) => NaN
y(x==0) = 1; % y(x==0) => 1
end
  1 个评论
Morten Nissov
Morten Nissov 2021-2-27
The usinc function works fine, the problem is the symbolic math produces equations with lots of ω terms in the denominator, which isn't realizable for small values of , which is very typical.

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Symbolic Math Toolbox 的更多信息

产品


版本

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by