Replace the diagonal with NaN in this 5x5 matrix

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Tesfaye Girma
Tesfaye Girma 2021-3-1
回答： Allen 2021-3-1
a=[1 0 0 0 0;0 1 0 0 0;0 0 1 0 0;0 0 0 1 0;0 0 0 0 1]
function y_diagonal =replace_NaN(x)
y=x;
end

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采纳的回答

Allen
Allen 2021-3-1
Another approach to this if you know that your original matrix will always be a square matrix. You can use the following:
a(eye(size(a))==1) = nan;

更多回答（1 个）

James Tursa
James Tursa 2021-3-1
You could use linear indexing for the diagonal. E.g., assuming x is square you could add this line to your function:
y(1:size(x,1)+1:end) = nan;

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