Spliting a date to day, month and year

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googo
googo 2013-5-16
Hello,
Suppose I have a date in this form only : 14/2/1923 or 8/2/1923 (not 14/02/1923 or 08/02/1923)
How can I split it to day, month and year? there are no zeros at all in the date.
Thank's!

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采纳的回答

José-Luis
José-Luis 2013-5-16
myDate = '4/2/1923';
mySplitDate = regexp(myDate,'/','split');
myDatevec = cellfun(@(x) str2double(x),mySplitDate)

更多回答（2 个）

Andrei Bobrov
Andrei Bobrov 2013-5-16
de = {'14/2/1923', '8/2/1923'};
ymd = datevec(de,'dd/mm/yyyy');
out = ymd(:,3:-1:1);
Jan
Jan 2013-5-16
Faster:
S = '14/2/1923';
D = sscanf(S, '%d/%d/%d', 3);
Or for cell strings:
S = {'14/2/1923', '23/12/1924'};
C = sprintf('%s*', S{:});
D = sscanf(C, '%d/%d/%d*', [3, length(S)]);

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