How to generate a list of random ID which can later be used instead of participant name?

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Parishad Bromandnia
评论： Parishad Bromandnia 2021-3-5
Hello every one,
I want to programm a code in which I can generate a list of random ID to use as test person ID later during my experiments.
- Each ID has to be consisted of 2 letters as well as 2 digits (e.g., 2g9e)
I would be so thankful if somebody could advise me how to do so.
Best regards,
Parishad

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Paul Hoffrichter
Paul Hoffrichter 2021-3-4
Due to the cyclist remark about homework, I am just starting the script. It leaves out certain patterns like 'a9a9' since it is just using combinations. How you rearrange the unique patterns is up to you.
a_26_2 = nchoosek('a':'z',2);
n_10_2 = nchoosek('0':'9',2);
a_26_2f = [a_26_2; fliplr(a_26_2)]; % gives 650 2 letter unique alpha strings
n_10_2f = [n_10_2; fliplr(n_10_2)]; % gives 90 2 letter unique numeric strings
By merging all possibilities, you can get 650*90 (almost 60,000) unique 4 char id's.

更多回答（1 个）

David Hill
David Hill 2021-3-4
Yes, a strictly numerical format would be much easier.
a=[randperm(10,2)+47;randperm(26,2)+96];
a=char(a(:)');
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