For loop with previous result

2021 3 5
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更新时间：2021 3 5
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for t=1:n
a(t)=600+10^t
b(t)=600-a(t)
end
I want that b to always taking the previous result
so, b(1)=600-a(1)
b(2)=(600-a(1))-a(2)
b(3)=(600-a(1)-a(2))-a(3)
how can i change the t

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Mathieu NOE
Mathieu NOE 2021-3-5

0 个投票

hello Jane
this is it :
at the k step : b(k) is 600 - sum of a from 1 to k
for t=1:n
a(t)=600+10^t;
b(t)=600-sum(a(1:t));
end

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