For loop with previous result

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Jane Smith
Jane Smith 2021-3-5
评论： Jane Smith 2021-3-5
for t=1:n
a(t)=600+10^t
b(t)=600-a(t)
end
I want that b to always taking the previous result
so, b(1)=600-a(1)
b(2)=(600-a(1))-a(2)
b(3)=(600-a(1)-a(2))-a(3)
how can i change the t

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采纳的回答

Mathieu NOE
Mathieu NOE 2021-3-5
hello Jane
this is it :
at the k step : b(k) is 600 - sum of a from 1 to k
for t=1:n
a(t)=600+10^t;
b(t)=600-sum(a(1:t));
end

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