false conditional still executed inside parfor

Question

Brandon Barker 2013-5-22

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/76568-false-conditional-still-executed-inside-parfor

I have a function that takes multiple arguments, and if there's more than one argument, a parfor will have some extra code run accessing the extra inputs:

function x = myfunc(arg1,arg2,arg3)
parfor ...
  if nargin > 1
    arg1[i] = arg2[i];
  end
  %continue with other calcs
end %end of parfor

The problem is, even if nargin == 1, it appears that arg2[i] is still being accessed, for example. Is there a way to get around this problem?

This is in MATLAB 2011a for Linux if that makes a difference.

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Edric Ellis 2013-5-22

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/76568-false-conditional-still-executed-inside-parfor#answer_86254

在 MATLAB Online 中打开

The PARFOR machinery recognises arg2 as a sliced input variable to the loop, and sends the slices off to the workers - it cannot recognise the fact that you're not using it because the code analysis does not eliminate the body of your "if" block. You need either to write multiple PARFOR loops, or you may be able to concatenate together the args that you need. For example:

    % assuming arg1 and arg2 are row vectors.
    if nargin > 1
       combinedArg = [arg1; arg2];
    else
       combinedArg = arg1;
    end
    parfor idx = ....
       tmp = combinedArg(:, idx);
       % Here, 'tmp' might be scalar, or 2x1
       if nargin > 1
          output(idx) = doStuff(tmp(1), tmp(2));
       else
          output(idx) = doStuff(tmp);
       end
    end