matrix array

1 次查看(过去 30 天)
Worravit nova
Worravit nova 2011-5-18
Dear Sir I need some help for matrix array. I have matrix 23x2 like this: 12 0 8 0 4 0 1 0 5 0 9 0 3 0 1 0 10 0 12 0 2 5 4 7 6 9 8 11 2 3 6 7 10 11 1 2 3 4 5 6 7 8 9 10 11 12
And I would like to separate it to two matrixes
1) With zeros in second Colum:
A=
12 0
8 0
4 0
1 0
5 0
9 0
3 0
1 0
10 0
12 0
2) Without zeros in second Colum:
B=
2 5
4 7
6 9
8 11
2 3
6 7
10 11
1 2
3 4
5 6
7 8
9 10
11 12
I have been used, nonzero but it will change my dimension to only one column. I need only non zeros in second Colum and value in first Colum that correspond to non-zeros in second Colum.
Anyone can suggest me please.
Thank you very much

回答(2 个)

Jarrod Rivituso
Jarrod Rivituso 2011-5-18
Would reshape followed by transpose do the trick....
%Create data array
data = [12 0 8 0 4 0 1 0 5 0 9 0 3 0 1 0 10 0 12 0 2 5 4 7 6 9 8 11 2 3 6 7 10 11 1 2 3 4 5 6 7 8 9 10 11 12]
%Reshape, then transpose
A = reshape(data(1:20),2,10)'
B = reshape(data(21:46),2,13)'

Andrei Bobrov
Andrei Bobrov 2011-5-18
variant
A = [12 0 8 0 4 0 1 0 5 0 9 0 3 0 1 0 10 0 12 0 ...
2 5 4 7 6 9 8 11 2 3 6 7 10 11 1 2 3 4 5 6 7 8 9 10 11 12];
N =find(A==0,1,'last');
A1 = reshape(A(1:N),2,[])';
A2 = reshape(A(N+1:end),2,[])';
If the matrix Ainput is as follows:
Ainput = [12 0
8 0
4 0
1 0
5 0
9 0
3 0
1 0
10 0
12 0
2 5
4 7
6 9
8 11
2 3
6 7
10 11
1 2
3 4
5 6
7 8
9 10
11 12];
then
N = find(all(Ainput,2),1,'first')-1
A1 = Ainput(1:N,:)
A2 = Ainput(N+1:end,:)
if
Ainput = [12 7
0 6
8 9
0 8
4 11
0 2
1 3
0 6
5 7
0 10
9 11
0 1
3 2
0 3
1 4
0 5
10 6
0 7
12 8
0 9
2 10
5 11
4 12]
as at the beginning of this an answer

类别

Help CenterFile Exchange 中查找有关 Matrices and Arrays 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by