Finding a bit value ?

3 次查看(过去 30 天)
Aleksander
Aleksander 2013-5-22
Hi. I have a value like a = 10101 this would change after how my program is run, but i will always use 0 or 1. so i consider this binary. now i would like to get the status of bit 5 i.e the first number (closest to the equal sign).
note!: the intention is to have the binary row decied which buttons are displayed in a gui.
this is what i have come up with
%code
for i = 0:4
count = i+1
if (bitget(main_sel2, count)==1)
set(handles.(sprintf('but%d', count))(:),'Visible','on');
else
set(handles.(sprintf('but%d', count))(:),'Visible','off');
end
end

回答(1 个)

Matt J
Matt J 2013-5-22
编辑:Matt J 2013-5-22
One way,
>> bits=fliplr(num2str(a)-'0'); bits(5)
ans =
1
  4 个评论
Aleksander
Aleksander 2013-5-25
Thanks, i tested it now and looks to work as i want :) Sine i am a nub can you try to enlighten me how fliplr actualy dose This ? Thanks.
Matt J
Matt J 2013-5-25
FLIPLR isn't doing anything significant. You posted that you want the indexing order of the bits to run from right to left (bit #5 is the leftmost bit). If you omit FLIPLR, you will be reading from left to right instead.

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Logical 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by