"How to remove the unwanted zero at the end in the floating point variable?"
Trailing zeros are just an artifact of displaying a specific binary value as a decimal number at a specific precision.
" a=1.006600000000000 but I want only 1.0066"
Binary floating point numbers do not store any information about how many decimal digits you want. Their precision is fixed to some number of binary digits, which cannot be changed. Both of your numbers are exactly the same:
a = 1.006600000000000;
b = 1.0066;
isequal(a,b)
When you round to some (decimal) magnitude, you might get the same number or a slightly different number, it really does not make much difference in this case because both of them will display as the same value anyway:
b = round(a,4)
isequal(a,b)
b+100*eps() % a slightly different number displays the same
If you are interested you can display the exact decimal value of any binary floating point number by downloading this FEX submission:
or view the HEX of the binary floating point (note they are exactly the same):
num2hex(a)
num2hex(b)
Summary: how numbers are displayed is not the same thing as how they are stored in memory. Do not confuse the storage of a number with its representation when displayed with a specific format:
If you want to convert to binary you need to specify if you mean:
- a number written in base 2
- some kind of encoded number (e.g. binary floating point)
Which do you want?
