for loop reference solution (from coursera) question

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Sorry if this is a stupid question, but I am pretty new to matlab, looking at this solution at the loop "for n=1:nint@" I can't see how this works as there isn't a variable allocated "n", just "nx" and "ny". and the other functions in the loop are functions of 'Z' or 'z'.

Many thanks for your help.

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Russel Burgess 2021-3-14

在 MATLAB Online 中打开

The for loop expression creates the variable, i.e.,

for n=1:nit

Will create a variable, n, initially set to 1. n is persistent, i.e., it will still exist after the foor loop is done - with the value nit, assuming nothing caused the for loop to break out early.

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