replacing rows with values from another matrix
显示 更早的评论
Hi,
i have 1 3625 x 1 matrix. i have used the following code to flip values based on an index. It gives me a matrix of 1185x1. (as expected)
next =1;
% figure out origin and flip the x and y axis accordingly
for i=1: length(pts)
x_values = flip(x(next:pts(i))) % this finds the walks that start at the other side of origin
next=pts(i);
end
this gives me the output i expect.
now where i am having trouble is with replacing the values in my previous matrix with these new values....
pts is 1250, 2434, 3624.
the new matrix x_values is from pts 1250 - 2434.
2 个评论
David Hill
2021-3-15
Not enough information to help. Showing sample of input and expected output would help. Your loop is over-riding x_values during each cycle of the loop. What does the pts() array look like?
caroline bourn
2021-3-16
采纳的回答
ANKUR KUMAR
2021-3-16
Since you have not attached any speciific data, I am generating random values and indices to change.
clc
clear
original_mat=randi(20,1,100);
new_mat=randi(20,1,30);
index_to_change=45:74;
original_mat(index_to_change)=new_mat;
Hope this helps.
3 个评论
caroline bourn
2021-3-16
ANKUR KUMAR
2021-3-17
clc
clear
[~, ~, raw] = xlsread('expected.xlsx','Sheet1','C1:D3624');
raw(cellfun(@(x) ~isempty(x) && isnumeric(x) && isnan(x),raw)) = {''};
cellVectors = raw(:,2);
raw = raw(:,1);
data = reshape([raw{:}],size(raw));
original_mat = data(:,1);
new_mat = cellVectors(:,1);
clearvars data raw cellVectors;
replace_index=cellfun(@(x) ~isempty(x) & isnumeric(x), new_mat);
original_mat(replace_index)=cell2mat(new_mat(replace_index));
updated_matrix=original_mat;
caroline bourn
2021-3-17
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Creating, Deleting, and Querying Graphics Objects 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
