field radiation pattern generation

please help me in writing code for attached file. i have written code like below but it is taking many hours for execution. so please help me for fast execution of equation in the attached file.
code i have written is
theta=[-90:0.01:90];
syms x
L=5;
A(x)=sym(1-(2*x/L)^2);
A(x)=(1-(2*x/L)^2);
phi(x)=sym(0)
phi(x)=0;
u=sin(theta);
fun=(A(x)*(exp((j*pi*10)*((u*x)+phi(x)))));
E= int(fun,x,-1,1)
Edb=20*log10(E);
plot(u,Edb);
grid on
title("radiation pattern");
help me what modifications i have to do for fast execution of this code

2 个评论

Does it have to be symbolic, or can we do it numerically where you define some range for your input?
@ramya k comment's moved here
we have to write numerically and we should get plot for that
please verify the attached file.. in that electric field equation available.. we have to execcute that equation.

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 采纳的回答

Use trapz
t = -90:90; % i choosed step 1
x = -1:0.1:1);
[T,X] = meshgrid(t,x);
u = sin(T);
A = ...%
fun = A.*exp(...);
E = trapz(x,fun,1);
plot(t,E)

7 个评论

tq for your idea, but i didnt get proper pattern, i got some scattered pattern when wrtten code according to your idea. i have uploaded required model pattern and what i got now. i am very new the matlab so please help me.
please attach the code
Range of X axis is [-1 1] here. BUt it's impossible since it's range of (x is integration variable, it disappears after integration)
The code and formulas are also not identical. but you assumed A=1 in your code
Can you collaborate?
A means amplitude, it can be anything like constant or circle or parabola. thats y i have taken constant as 1 in first execution.
i made some correction to your code
clc,clear
t = -90:90;
x = -1:0.1:1
[T,X] = meshgrid(t,x);
u = sin(T);
A = 1;
phi = 0;
fun = A.*exp(1j*pi*10*(u.*X+phi));
E = trapz(X,fun,1);
Edb = 20*log10(E);
plot(t,E)
thank you so much for your help

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