Display strings and variable - cell array
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I want to disply the output of my variable. so i created the following code.
food= { 'Rice','Quinoa','Tortilla','Lentils','Broccoli' }';
X % X is the output
for n =1:length(X)
disp(food{X(ii)})
end
The code is not working. Any help will be appreciated.
回答(1 个)
ANKUR KUMAR
2021-3-15
编辑:ANKUR KUMAR
2021-3-15
Access the contents of cells by indexing with curly braces, {}.
food= { 'Rice','Quinoa','Tortilla','Lentils','Broccoli' }';
for n =1:length(food)
disp(food{n})
end
5 个评论
Telema Harry
2021-3-15
ANKUR KUMAR
2021-3-15
It is not necessary to assign X to food.
If you have specific indices in X to choose from food variable, you can use this chunk of code
food= { 'Rice','Quinoa','Tortilla','Lentils','Broccoli' }
X=[2,5]
for n =1:length(X)
disp(food{X(n)})
end
Telema Harry
2021-3-15
ANKUR KUMAR
2021-3-15
Please clear all the pre defined variables before running the code.
Index cannot be float. It must be an integer.
Below is the working complete code.
clc
clear
food= { 'Rice','Quinoa','Tortilla','Lentils','Broccoli' }
X=[2,5]
for n =1:length(X)
disp(food{X(n)})
end
Telema Harry
2021-3-17
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