solution for algorithm to link status?

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ankanna 2021-3-17

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/775567-solution-for-algorithm-to-link-status

评论： ankanna 2021-4-8

nodes = 3; m = 0.7
for i = 1:nodes
    for j = i+1:nodes
        test = unifrnd(0,1)
        if ni = 1
        nj = 1:nodes
        if  (test<=m/ni=1/nj=1)
            li,j = 1
        else
            li,j = 0
        end
            lj,i = li,j
        end
        L = li,j;lj,i
end

please to generate this

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采纳的回答

Walter Roberson 2021-3-17

1
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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/775567-solution-for-algorithm-to-link-status#answer_650232

编辑：Walter Roberson 2021-3-17

在 MATLAB Online 中打开

nodes = 3; m = 0.7;
for i = 1:nodes
    for j = i+1:nodes
        test = unifrnd(0,1);
        if ni == 1
            nj = 1:nodes;
            if  (test<=m/ni==1./nj==1)
                l(i,j) = 1;
            else
                l(i,j) = 0;
            end
            l(j,i) = l(i,j);
        end
        L = [l(i,j);l(j,i)];
    end
end

However, we can prove that the if (test<=m/ni==1./nj==1) will be false except when nodes = 1 (in which case the code is just rather strange but could be true sometimes.)