Creating a frequency table

Hello,
suppose I have a vector in legnth of 100 that contains a number between 1-4 how can I make a frequncy vector using the data in the vector? I'd tryed the function tabulate but if there is no 4 or 3 for example it will not be in the table and I want it to be there just with the value 0.
Thank's!

3 个评论

This is not clear
Ok, sorry.
For example : [4 3 2 2 4 3 3] {only numbers between 0-4}
I'm looking for a function that will return a frequency vector :
0
0
2
3
4
That's simply the histogram - I think - and you can use histc() or hist(). It's "I think" because I'm not sure why you say there are four 4's when I only see 2. The histogram would say there is two 4's in [4 3 2 2 4 3 3]. Perhaps you can explain your thought process around how you came up with four 4's.

请先登录,再进行评论。

 采纳的回答

a=arrayfun(@(z) sum(ismember(x,z)),0:4)'
out=[(0:4)' a 100*a/numel(x)]

更多回答(2 个)

x=[1 1 2 2 1 2 ];
a = histc(x(:),0:4);
out = [(0:4)', a, a/sum(a)*1e2];
x=[1 1 2 2 1 2 ]
y=[x 5]
out=tabulate(y)
out(end,:)=[]

6 个评论

>> x=[1 1 2 2 1 2 ];
y=[x 5];
out=tabulate(y);
out(end,:)=[];
>> out
out =
1.0000 3.0000 42.8571
2.0000 3.0000 42.8571
3.0000 0 0
4.0000 0 0
it was suppose to be
0 0 0%
1 3 50%
2 3 50%
3 0 0%
4 0 0%
didn't understand the purpose of the "5" in your code. Thank's!
You said between 1 and 4
googo
googo 2013-5-31
编辑:googo 2013-5-31
ho... sorry.. my mistake but anyway why it's 42.85% an not 50%?
If there is no 4 in your list, tabulate will not show 4 0 0 like you said, To resolve the problem,I've added 5 and removed its result
x=[1 1 2 2 1 2 ];
[0:4 ;histc(x,0:4)]'
Iman , make it as an answer

请先登录,再进行评论。

类别

帮助中心File Exchange 中查找有关 Discrete Data Plots 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by