How to find the number of consecutive occurrence of the numbers?
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I'm in need to get the number of consecutive occurrence of the numbers in an array. Here is an example,
A=[1,2,3,1,2,3,1,1,1];
unqA=unique(A);
count=histc(A,unqA);
It give the count of 1 as 5, then 2 and 3 as 2. In the array A, the consecutive occurrence of 1 is 3 (i.e., maximum occurrence). Please help me how to get the value as 3 for the array A.(just for example).
Thanks in advance.
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Roger Stafford
2013-5-31
It isn't clear if you are asking for the maximum consecutive occurrence for each possible number in A or the maximum of these maximum occurrences. Here is a way to find the latter.
p = find([true,diff(A)~=0,true]);
[c,q] = max(diff(p));
m = A(p(q));
The pair (m,c} gives the number occurring consecutively the largest number of times and the number of those times, respectively.
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更多回答(2 个)
Azzi Abdelmalek
2013-5-31
A=[1,2,2,3,1,2,3,1,1,1];
ii=num2str(diff(A));
ii(strfind(ii,' '))=[];
jj=regexp(ii,'[^0*]','split');
jj(strcmp(jj,''))=[];
out=max(cellfun(@numel,jj))+1
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per isakson
2013-5-31
I think you can find solutions in Cody too.
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Jan
2013-5-31
编辑:Jan
2013-5-31
@Bless: On http://www.n-simon.de/mex you find download links for RunLength.mexw64 and RunLength.mexw32 for current Matlab versions, and RunLength.dll for Matlab versions before 7.6. All are compiled for Windows. If you use a Linux or Mac, you have to install a compiler and follow the shown instructions.
In addition you can use the M-file RunLength_M also.
Feel free to send me the complete error message by email and explain, why you do not get compiled MEX files from the download page.
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