How to get this into a loop

1 次查看(过去 30 天)
Hi there i like to ask how can i get this into a for loop
x=rand(1,20)
h1=(x(2,1)-x(1,1));%First interval
h2=(x(3,1)-x(2,1)); %second interval
h3=(x(4,1)-x(4,1));%Third interval
h4=(x(5,1)-x(4,1));
I like the interval to run for another 20 times
i get it as
for i=1:20
h=( x(1,n) -x(1,(n-1)
iter=iter+1
end
Through this method, i can get 20 iterations but the h is remain the same value, can i know why and how can i change it to get the right way
  1 个评论
Jan
Jan 2021-3-18
x = rand(1, 20)
h1 = x(2,1) - x(1,1); %First interval
This must fail: x has one row only, than x(2,1) does not exist. Please post some working code.

请先登录,再进行评论。

采纳的回答

David Hill
David Hill 2021-3-18
x=rand(1,20);
for k=1:19
h(k)=x(k+1)-x(k);
end
Or without loop
x=rand(1,20);
h=diff(x);
  2 个评论
Mark Loui
Mark Loui 2021-3-18
Hi thanks so much, i have another question
For example
x=rand(1,20);
for k=1:19
h(k)=x(k);
end
Can this be done?
As from what i seen it keeps getting the same output?
David Hill
David Hill 2021-3-18
You do not need a loop to set h=x
x=rand(1,20);
h=x;%h is an array

请先登录,再进行评论。

更多回答(1 个)

Jan
Jan 2021-3-18
编辑:Jan 2021-3-18
Why do you want a loop? It is working without a loop also - guessing that you mean x(1, 2) and not x(2, 1) as in the code in the question:
x = rand(20, 20)
h1 = x(:, 2) - x(:, 1); % First interval
h2 = x(:, 3) - x(:, 2); % second interval
h3 = x(:, 4) - x(:, 4); % Third interval
h4 = x(:, 5) - x(:, 4);
  3 个评论
Mark Loui
Mark Loui 2021-3-18
Hi there i got it already thanks.
But i have another question, i like to create a diag function with a loop where the matrix is depending on the nxn size, how can i do it ?
After creating the element i like to fill in each of the element with a value, i am having trouble with this matter and not able to get the right approach, please help
Jan
Jan 2021-3-18
What do you want your "diag function with a loop" to do? The explanation " matrix is depending on the nxn size" is not clear enough yet.

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

产品


版本

R2020a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by