Detect the error position in a vector and correct it (Matlab)

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Afluo Raoual 2021-3-18

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评论： Afluo Raoual 2021-3-18

采纳的回答： Christopher McCausland

Dear members;

I have the code word C of length 'M' and I have also the received vector V after decoding of the same length 'M' as C

For example:

V=[1 0 0 1 0 1 0 1 0 0]

C=[1 1 0 1 0 0 0 1 0 0]

I want firstly detecting the position of each bold bit of V and than correct it by adding 1 to those bits (because in mod2: 0+1=1 and 1+1=0) in order to obtain V=C

How can I do that please

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Adam Danz 2021-3-18

> I want firstly detecting the position of each bold bit of V

Ah, so what you really want to do is find the index of the vector where V(i) is not equal to C(i).

Afluo Raoual 2021-3-18

Exactly yes, and then correct the bold bits of V in order to obtain them equal to C

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Christopher McCausland 2021-3-18

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Hi Afluo,

You can try something like the below to assess where the diffrences between the arrays are; after this just cycle to these locations and change the value as you need.

I hope this helps,

Christopher

V=[1 0 0 1 0 1 0 1 0 0]
C=[1 1 0 1 0 0 0 1 0 0]
diff_Check = V ~= C;

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Adam Danz 2021-3-18

编辑：Adam Danz 2021-3-18

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I agree with Christopher McCausland , this does describe what you want to do but is missing the final step which is quite straightforward and something you could fill in yourself,

V=[1 0 0 1 0 1 0 1 0 0];
C=[1 1 0 1 0 0 0 1 0 0];
V(V~=C) = V(V~=C) + 1; 
mod(V,2)
ans = 1×10
     1     1     0     1     0     0     0     1     0     0