plotting in a for loop
显示 更早的评论
Hello, I am trying to plot in a while loop and I am having trouble figuring out how to set this up. I am calling a function that I have written to vary the x component of the vector from -20 to 20 in increments of 5. The code for the function and the file I am using are shown below.
Code:
x1=-1;
y1=0;
z1=0;
x2=1;
y2=0;
z2=0;
x=-25;
y=5;
z=0;
while x<20
x=x+5
vortexsegment(x1,y1,z1,x2,y2,z2,x,y,z);
end
Function:
function[Vx,Vy,Vz]=vortexsegment(x1,y1,z1,x2,y2,z2,x,y,z);
S=[x1,y1,z1]; % defining points for start
E=[x2,y2,z2]; % defining points for end
R=[x,y,z]; % defining points for point of interst
A=S-R; % Finding vector a
B=E-R; % Finding vector b
Z1=cross(A,B);
Z2=dot(A,B);
MagA=norm(A);
MagB=norm(B);
q=(Z1./(dot(Z1,Z1))).*(MagA+MagB).*(1-(Z2./(MagA.*MagB)));
V=(1./(4.*3.14)).*q
Vx=V(1,1)
Vy=V(1,2)
Vz=V(1,3)
Thanks
采纳的回答
Image Analyst
2013-6-3
Did you try to plot Vx?
while x < 20
x=x+5
[Vx, Vy, Vz] = vortexsegment(x1,y1,z1,x2,y2,z2,x,y,z);
plot(Vx, 'b-', 'LineWidth', 3);
grid on;
drawnow;
end
2 个评论
Christopher
2013-6-3
Image Analyst
2013-6-3
That's called accepting the return arguments into variables in the calling routine, or something like that. vortexsegment() calculates them and sends them back to the caller, but unless the calling routine accepts them into variables, they are thrown away.
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 MATLAB 的更多信息
2013-6-3
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
