Matlab function inside Simulink gives parse error

Question

Wouter 2013-6-3

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/77845-matlab-function-inside-simulink-gives-parse-error

回答： Christopher Magana 2018-11-30

I have included the Matlab Function block in a Simulink diagram to call a matlab function, http://www.mathworks.nl/help/simulink/slref/matlabfunction.html.

Now when I want to simulate the Simulink diagram I get the error:

Errors occurred during parsing of MATLAB function 'MATLAB Function'(#384)

I however do not find any errors in my matlab function script:

 function out = Sigma(xyz,x1,u)
 x = xyz(1);
 y = xyz(2);
 z = xyz(3);
 out = [-x^3 + 3*x + 2 + 5*y - z + u; ...
        -0.8 - x^2 - 2*x - y;         ...
        0.005*(4*(x1 + 1.77) - z)];
 end

The input xyz is a mux-ed signal with length 3, x1 and u are scalar values.

So what is going wrong? Can anyone look threw my files?

https://dl.dropboxusercontent.com/u/20782274/matlab.zip

It contains three files. - main.m, the main file in some variables are declared and which runs the simulink model - Sigma.m, a copy of the matlab function - HindmarshRose.mdl, the simulink model.

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Kaustubha Govind 2013-6-3

编辑：Kaustubha Govind 2013-6-3

Please scroll down through the list of errors in the popup window and see if you can find more details about the error, especially one pointing to a line number in your code.

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Answer 1

Wouter 2013-6-8

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/77845-matlab-function-inside-simulink-gives-parse-error#answer_88156

在 MATLAB Online 中打开

It turns out you have to initialize the output before calling any Matlab code since otherwise Matlab does not know the length of the output.

function out = Sigma(xyz,x1,u)
 out = zeros(3,1);
 x = xyz(1);
 y = xyz(2);
 z = xyz(3);
 out = [-x^3 + 3*x + 2 + 5*y - z + u; ...
        -0.8 - x^2 - 2*x - y;         ...
        0.005*(4*(x1 + 1.77) - z)];
end