How can I find the integral of normpdf(X,1,0) from -inf to inf?
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How can I find the integral of normpdf(x,1,0) from -inf to inf?
The followings did not work:
F = @(x)normpdf(x, 0, 1);
Q = quad(F,-Inf,Inf);
---------
syms x;
int('normpdf(x,0,1)',-inf,inf)
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回答(2 个)
Wayne King
2013-6-4
F = @(x)normpdf(x, 0, 1);
Q = integral(F,-Inf,Inf);
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Colin
2019-3-17
F = @(x)normpdf(x, 0, 1);
Q = integral(F,-Inf,Inf);
This works nicely, but this:
F = @(x)normpdf(x, 350, 20);
Q = integral(F,-Inf,Inf);
gives
Q = 3.4540e-29
Seems likes it's not very robust.
Wayne King
2013-6-4
编辑:Wayne King
2013-6-4
integral() was introduced in R2012a. It is used to numerically evaluate an integral, not symbolically and integral() can be unused on unbounded sets like (-Inf,Inf)
Again, in your case you can use quad() far short of (-Inf,Inf) and get 1.
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