Why do i get the error "Dimensions of arrays being concatenated are not consistent"

Question

Umut Ayyildiz 2021-3-23

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/780592-why-do-i-get-the-error-dimensions-of-arrays-being-concatenated-are-not-consistent

评论： Umut Ayyildiz 2021-3-23

采纳的回答： William

在 MATLAB Online 中打开

Why do I get this error for one but not the other even though the two codes are the exact same.

This one runs fine:

clear all; close all
% Initial Conditions
th= 0.01*pi/180; % initial theta position (rad)
w=0;  % inital theta velocity (rad/s)
g=9.81; %gravity constant (m/s^2)
L=0.3; % length of bar (m)
mB=2; % mass of bar (kg)
mA=1; %mass of collar (kg)
dt=.001;
I = (mB*L^2)/12;
Wa=mA*g;
Wb=mB*g;
x=(mB*L)/2;
z=(L/2);
for ii = 1:5000
    A = [-1 0 0 -mA 0
        0 -1 1 0 0
        1 0 0 -mB -x*cos(th)
        0 1 0 0 x*sin(th)
        sin(th)*z -cos(th)*z 0 0 -I];
    B = [0; Wa; x*(w)^2*sin(th); Wb-x*(w)^2*cos(th); 0];
    X=inv(A)*B;
    w = w + X(5)*dt;
    th=th + w*dt;
    
    time(ii)= ii*dt;
    theta(ii)=th;
    alpha(ii)= X(5);
    omega(ii)=w;
    Rx(ii)=X(1);
    Ry(ii)=X(2);
    N(ii)=X(3);
    d_acc(ii)=X(4);
end

But this one gives me an error:

clear all; close all
% Initial Conditions
theta= 0.01*pi/180; % initial theta position (rad)
theta_V=0;  % inital theta velocity (rad/s)
g=9.81; %gravity constant (m/s^2)
L=0.3; % length of bar (m)
mB=2; % mass of bar (kg)
mA=1; %mass of collar (kg)
dt=.001;
I = (mB*L^2)/12;
Wa=mA*g;
Wb=mB*g;
x=(mB*L)/2;
z=(L/2);
for i = 1:5000
    A = [-1 0 0 -mA 0;
        0 -1 1 0 0;
        1 0 0 -mB (-x*cos(theta))
        0 1 0 0 x*sin(theta)
        (sin(theta)*z) (-cos(theta)*z) 0 0 -I];
    B = [0; Wa; x*(theta_V)^2*sin(theta); Wb-x*(theta_V)^2*cos(theta); 0];
    X=inv(A)*B;
    theta_V = theta_V + X(5)*dt;
    theta=theta + theta_V*dt;
    
    time(i)= i*dt;
    theta(i)=theta;
    theta_a(i)= X(5);
    omega(i)=theta_V;
    Rx(i)=X(1);
    Ry(i)=X(2);
    N(i)=X(3);
    d_acc(i)=X(4);
end

I was changing my code from the one that worked because I realized I messed up my dynamic equations and I ended up with the same error I mention in the title When I was trying to debug it by backtracking I realized that even my original code was giving me an error. I had another file saved with my orignal code and it runs.

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

William 2021-3-23

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/780592-why-do-i-get-the-error-dimensions-of-arrays-being-concatenated-are-not-consistent#answer_655372

The problem in the second program is the statement 'theta(i) = theta', which is changing theta from a scalar into a vector. Then on the second iteration for the for-loop, the matrix A has some elements that are now vectors.

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

Umut Ayyildiz 2021-3-23

I see what you mean, in the first code theta is being saved into another variable so when it goes to the next iteration it isnt a vector but still a scalar. Thank you!

请先登录，再进行评论。