Performing Action to ALL 'struct' Variables

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Philip 2011-5-19

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https://ww2.mathworks.cn/matlabcentral/answers/7806-performing-action-to-all-struct-variables

编辑： per isakson 2018-2-25

采纳的回答： Matt Fig

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Is there a way to perform the same action on several variables of type 'struct'?

In my case, I have 30 separate 'struct' variables (with non-logical names), and each of them contains a single vector of 200 elements. I only want to deal with the second half of these elements so I need something like:

struct_name = struct_name.data(100:end)

But need to keep the name of the struct variable intact. Does anyone have any suggestions?

I hope this made sense!

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Matt Fig 2011-5-19

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% Create several structures with different names...
structn.dat = 1:10;
structm.dat = 1:10;
structk.dat = 1:10;
% Now edit the data.
save mystructs structn structm structk
X = load('mystructs');
F = fieldnames(X);
for ii = 1:length(F)
    X.(F{ii}).dat = X.(F{ii}).dat(5:10);
end
% Check
X.structm.dat

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Philip 2011-5-19

Perfect - thanks for your help!! Now to work out how to get just the last 100 elements for each!

Thanks again!

Walter Roberson 2011-5-19

编辑：per isakson 2018-2-25

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SFN = fieldnames(MyStruct);
for K = 1 : length(SFN)
    var_name = SFN{K};
    VFN = fieldnames(MyStruct.(var_name));
    for N = 1 : length(VFN)
        this_field = VFN{N};
        if isvector(MyStruct.(var_name).(this_field)) & ...
                length(MyStruct.(var_name).(this_field)) > 100
            MyStruct.(var_name).(this_field) = MyStruct.(var_name).(this_field)(1:100);
        end
    end
end

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Fangjun Jiang 2011-5-19

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Would this help?

a(200).b=1;
a(200).c=0;
NewStruct=a(100:end);

Or, Do you mean keep the struct variable name, not the field names:

a(1:99)=[];

Now I think you mean this:

a.Data=1:200;
a.Data(1:100)=[]

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Philip 2011-5-19

Apologies - I feared I wasn't very clear.

I meant to say that I have 30 separate variables (of type 'struct'), and each of these has a different name (i.e. fh, cy, de, it etc..). Now, instead of each of them containing 200 elements, I want to 'update' each of them so that they each contain only the last 100.

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