Subscripted assignment dimension mismatch

2 次查看（过去 30 天）
Andre
Andre 2013-6-5
I know what the error mean. But I cant see why iam getting it.
for h=1:2
%%DFT
X(h,:)=fft(u(h,:)); get the error in this line
.
.
.
end
>> size(u(h,:))
ans =
1 60000
>> size(u)
ans =
2 60000
  2 个评论
Mark
Mark 2013-6-5
Does X exist already when you reach that line? Is it at least 2 x 60000 in size?
Andre
Andre 2013-6-5
Thats it. The X was stated earlier in the script.

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