Growing Diagonal Matrix Problem

2021 3 23
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更新时间：2021 3 24
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I am trying to create a diagonal matrix that can grow a # of rows and # of collumns. These collumns can be from a range of 10 to 100000 to infinite but must maintain a pattern.
For simplicity I am using a 9x9 Matrix. It seems like it is repeating 3 matrics over and over.
1 - Diagonal
1 - Ones Diagonal
1 - Zeros
A B 0 1 0 0 0 0 0
B A B 0 1 0 0 0 0
0 B A 0 0 1 0 0 0
1 0 0 A B 0 1 0 0
0 1 0 B A B 0 1 0
0 0 1 0 B A 0 0 1
0 0 0 1 0 0 A B 0
0 0 0 0 1 0 B A B
0 0 0 0 0 1 0 B A
I am having a hard time trying to seeing how to write this.

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回答（1 个）

Matt J
Matt J 2021-3-23
编辑：Matt J 2021-3-24
Ran in:

0 个投票

Ran in:
A=3; B=4;
M=[A B 0; B A B; 0 B A];
n=3;
e = ones(n,1);
Q = spdiags([e 0*e e],-1:1,n,n);
%Q=toeplitz(sparse([0,1,zeros(1,n-2)]));
result =kron(speye(n),M)+kron(Q,eye(3));
full(result)
ans = 9×9
3 4 0 1 0 0 0 0 0 4 3 4 0 1 0 0 0 0 0 4 3 0 0 1 0 0 0 1 0 0 3 4 0 1 0 0 0 1 0 4 3 4 0 1 0 0 0 1 0 4 3 0 0 1 0 0 0 1 0 0 3 4 0 0 0 0 0 1 0 4 3 4 0 0 0 0 0 1 0 4 3

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WARRIOR24
WARRIOR24 2021-3-23
I need the big matix to be changable, like if the 9x9 can be change to a 100x100. The 9x9 is just an example.
Matt J
Matt J 2021-3-23
I know it's just an example. So is the value of n=3 in my code.
WARRIOR24
WARRIOR24 2021-3-23
Here is my next problem, what is it need to be changed to 8x8? But keep everything the same except the last row and collumn?
Matt J
Matt J 2021-3-23
If you mean you want to remove the last row and column, then,
result(:,end)=[]; %remove last column
result(end,:)=[]; %remove last row

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WARRIOR24
WARRIOR24
2021-3-23

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Matt J
Matt J
2021-3-24

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