replacing blank values in a single column cell array with the previous value
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basically i have a list of values in a cell array.
A =
'-2.0372681e-10'
'0'
'-1.1641532e-10'
'-2.910383e-11'
' '
' '
'-1.45579e-11'
'0'
' '
'2.9103759e-11'
' '
'1.455188e-11'
'-2.910383e-11'
'7.2759396e-11'
'-1.45579e-11'
'2.9103759e-11'
'-4.3655746e-11'
'8.7311276e-11'
I want all the blanks to be filled with whatever the previous cell value is
1 个评论
Sean de Wolski
2011-5-19
What do you want to do if the first entry is blank?
采纳的回答
Andy
2011-5-19
Pending the answer to Sean de's comment, I will assume the first entry is not blank:
for ix=2:length(A)
if isempty(A{ix})
A{ix} = A{ix-1};
end
end
EDIT: As per Sean de's suggestion, the for loop now starts at 2. Michael, you may have to adjust this if the first element is allowed to be blank. (The code will not cause an error, but the result will not be what you intended.)
1 个评论
Sean de Wolski
2011-5-19
This is probably just as good as any vectorized solution since we're dealing with cell arrays. +1!
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