replacing blank values in a single column cell array with the previous value

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Michael
Michael 2011-5-19
basically i have a list of values in a cell array.
A =
'-2.0372681e-10'
'0'
'-1.1641532e-10'
'-2.910383e-11'
'&nbsp'
'&nbsp'
'-1.45579e-11'
'0'
'&nbsp'
'2.9103759e-11'
'&nbsp'
'1.455188e-11'
'-2.910383e-11'
'7.2759396e-11'
'-1.45579e-11'
'2.9103759e-11'
'-4.3655746e-11'
'8.7311276e-11'
I want all the blanks to be filled with whatever the previous cell value is

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Andy
Andy 2011-5-19
Pending the answer to Sean de's comment, I will assume the first entry is not blank:
for ix=2:length(A)
if isempty(A{ix})
A{ix} = A{ix-1};
end
end
EDIT: As per Sean de's suggestion, the for loop now starts at 2. Michael, you may have to adjust this if the first element is allowed to be blank. (The code will not cause an error, but the result will not be what you intended.)

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