Pearsons correlation using corrcoef not working

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I am trying to calculate the pearsons correlation between two variables in a timetable. I am utalising the corrcoef() function. However the output it gives me is always NaN NaN NaN NaN. Why is this? How can I fix this?
  4 个评论
William Rose
William Rose 2021-3-24
Are the variables (vectors) which you are trying to correlate both numbers (not strings or times or dates), with the same length?
If you provide the timetable, and the code that does not work, as attached files, it will help others help you. An example of corrcoeff() operating on two columns from a table is below.
>> height=1.7+0.2*randn(10,1);
>> weight=70+10*randn(10,1);
>> T=table(height,weight);
>> corrcoef(T.height,T.weight)
ans =
1.0000 0.2262
0.2262 1.0000
Elizabeth Lees
Elizabeth Lees 2021-3-24
@William Rose Thank you for your answer. I have discovered it was because many rows of the numerical data contained NaN values, I have now used 'Rows', 'Pairwise' to discard these in the statistics and am now recieving results. However when just the NSE() function to calculate the Nash-Sutcliffe value between the variables I am still getting an NaN result I believe for the same problem however 'Rows', 'Pairwise' doesn't seem to work within the NSE() function, do you know of another way to discard these empty rows to calculate the Nash-Sutcliffe?
Example code:
NSE(combined_data.Observed_Rio_Branco,combined_data.Simulated_Rio_Branco, 'Rows', 'pairwise')
Error using NSE
Too many input arguments.

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采纳的回答

William Rose
William Rose 2021-3-24
This code eliminates each row with one or more NaNs. Thank you to @Jan for this.
X = rand(10, 4);
X(X < 0.1) = NaN;
disp(X); %array containing NaNs
X(any(isnan(X), 2), :) = []; %delete rows with NaN
disp(X) %array with NaN rows removed
  1 个评论
William Rose
William Rose 2021-3-24
Assumng your input data are column vectors, you would do
%make a Nx2 array
A=[combined_data.Observed_Rio_Branco,combined_data.Simulated_Rio_Branco];
A(any(isnan(A), 2), :) = []; %delete rows with NaN
NSE(A(:,1),A(:,2));
I do not have the NSE() function so I cannot test the code above.

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