how to run c at intervals [0, 1] with a jump of 0.5

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Relly Syam 2021-3-25

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https://ww2.mathworks.cn/matlabcentral/answers/783133-how-to-run-c-at-intervals-0-1-with-a-jump-of-0-5

编辑： Relly Syam 2021-3-25

s=3; E=[]; for i=1:s for j=1:s E(i,j)=euler(i,c); end end E

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KSSV 2021-3-25

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https://ww2.mathworks.cn/matlabcentral/answers/783133-how-to-run-c-at-intervals-0-1-with-a-jump-of-0-5#answer_657808

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c = 0:0.5:1

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KSSV 2021-3-25

E is a cell now...you need to access using: E{1}, E{2}

Relly Syam 2021-3-25

编辑：Relly Syam 2021-3-25

I don't understand the flow. I want to make a matrix [E1(c1) E1(C2) ... E1(Cn); E2(C1) E2(C2) .. E2(Cn); .....; En(C1) En(C2) ... En(Cn)].

so when n = 3 then we get C1 = 0, C2 = 1/2, C3 = 1. and the matrix [E1(c1) E1(C2) E1(C3); E2(C1) E2(C2) E2(C3); E3(C1) E3(C2) E3(C3)] where the result is [-0.5 0 0.5; 0 -0.25 0; 0.25 0 -0.25]. because I want to multiply the results of the matrix above with another matrix.

E=euler(i, j) % i=1:n and j=1:n

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