Output variable of a function as an input of another function - Problem
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Hello,
I got two ".m" files, the first one is called "Ex_1" and the second one is called "Ex_2" as shown bellow. Output of Ex_1 must be the Input of Ex_2. How can I make function Ex_2 understand the values of a, b? Is there anyway to call variable a and b from Ex_1 in Ex_2? Thanks for your time, appreciate your help!
function [a,b]=Ex_1(dat) %dat is just a variable which I load in my program
x=log10(dat(:,1));
y=dat(:,2);
P=size(dat,1);
SSxy=sum(x.*y)-(sum(x)*sum(y)/P);
SSxx=sum(x.^2)-((sum(x))^2/P);
a=SSxy/SSxx
y_bar=sum(y)/P;
x_bar=sum(x)/P;
b=y_bar-a*x_bar
end
function [freq]=Ex_2(a,b,db) %a, b is the same a, b of function Ex_1. db value doesn't matter
freq=(db-b)/a;
end
2 个评论
David Hill
2021-3-25
I don't understand your question. You are currently providing a,b,and db as inputs to function Ex_2. Why have two functions? Why not just provide Ex_1 with dat and db?
Christos Tsallis
2021-3-25
编辑：Christos Tsallis
2021-3-25
采纳的回答
drummer
2021-3-25
Did you do a third procedural script calling both of them?
You could do like this in your third script.m:
[a, b] = Ex_1(data);
%% % by doing this break, you can check if a and b were loaded into your workspace
% once they were loaded, you can now call your second script by
[freq] = Ex_2(a, b, db); % assuming you´re loading db variable mannualy.
This is not necessarily the only thing you could do. You could also type these lines in your command window.
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