Solving equation with tan

6 次查看(过去 30 天)
I have an equation that needs to be solved numerically.
-125=-arctan(0.25*x)-0.2*x*180/pi
I know that the answer can be approximatedto 6, according to the exams "corrected answer"
I cant solve it with pen and paper so I wonder if there is anyway to solve this in MATLAB?

采纳的回答

Star Strider
Star Strider 2021-3-25
Here is how I would solve it:
fcn = @(x) 125-atand(0.25.*x)-0.2*x*180/pi;
est_x = fzero(fcn, 10)
producing:
est_x =
5.9959
See the documentation for fzero for details.

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Logical 的更多信息

标签

产品


版本

R2019a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by